Kasr sonlar :: Yechimlar

Masala A

Masala sharti

Berilgan ikkita kasr sonni qo‘shadigan dastur tuzing.

Kiruvchi ma'lumot

Har bir qatorda a/b ko‘rinishidagi kasr son. a ning qiymat -100 dan 100 gacha, b ning qiymat 2 da 100 gacha.

Chiquvchi ma'lumot

Berilgan ikkita kasr sonning yig‘indisi

#include <stdio.h>
#include <itboom.h>

int main() {
    int a, b, c, d;
    scanf("%d/%d", &a, &b);
    scanf("%d/%d", &c, &d);
    
    int num = a * d + b * c;
    int den = b * d;
    
    //qisqarmas karga o'tkazish uchun EKUB ga bo'lamiz
    int k = gcd(num, den);
    
    printf("%d/%d", num / k, den / k);
    
    return 0;
}

import math
from fractions import Fraction

def main():
    a = Fraction(input())
    b = Fraction(input())
    c = a + b
    
    # shartda 1 emas, 1/1 qabul qilinadi deyilgan
    print(f"{c.numerator}/{c.denominator}")

if __name__ == '__main__':
    main()

Masala B

Masala sharti

Kiritilgan kasr sonni o‘nli kasr (\(\frac{a}{10^n}\)) ko‘rinishida ifodalash mumkin bo‘lsa, shu kasr sonni, aks holda NO so‘zini ekranga chiqaradigan dastur tuzing.

Kiruvchi ma'lumot

Birinchi qatorda a/b ko‘rinishidagi kasr son. Bu yerda a ning qiymat \(-10^5\) dan \(10^5\) gacha, b ning qiymat \(2\) dan \(10^{8}\) gacha

Chiquvchi ma'lumot

Masala shartidagi qiymatlar

#include <stdio.h>
#include <itboom.h>

int main() {
    long a, b;
    scanf("%lld/%lld", &a, &b);
    
    long n = b;
    
    while(n > 1) {
        if (n % 2 == 0) {
            a *= 5;
            b *= 5;
            n /= 2;
        } else if (n % 5 == 0) {
            a *= 2;
            b *= 2;
            n /= 5;
        } else {
            printf("NO");
            return 0;
        }
    }

    printf("%lld/%lld", a, b);
    
    return 0;
}

import math
import itboom

def main():
    a, b = map(int, input().split("/"))
    n = b
    while n > 1:
        if n % 2 == 0:
            a, b, n = a * 5, b * 5, n // 2
        elif n % 5 == 0:
            a, b, n = a * 2, b * 2, n // 5
        else:
            print("NO", end="")
            return
        
    print(f"{a}/{b}")

if __name__ == '__main__':
    main()

Masala C

Masala sharti

Kiritilgan songa teskari sonni aniqlaydigan dastur tuzing.

Kiruvchi ma'lumot

Birinchi qatorda a/b ko‘rinishidagi kasr son. a ning qiymati \(-10^8\) dan \(10^8\) gacha, b ning qiymat \(2\) dan \(10^8\) gacha.

Chiquvchi ma'lumot

Kiritilgan songa teskar soni

#include <stdio.h>
#include <itboom.h>

int main() {
    int a, b;
    scanf("%d/%d", &a, &b);
    
    int n = 1;
    if (a < 0) {
        n = -1;
        a = -a;
    }
    
    printf("%d/%d", n * b, a);

    return 0;
}

import math
import itboom
from fractions import Fraction

def main():
    a, b = input().split("/")
    
    if a.startswith("-"):
        a = a[1:]
        b = "-" + b
    
    print(f"{b}/{a}")
    
if __name__ == '__main__':
    main()

Masala D

Masala sharti

Kiritilgan kasr sonni aralash son shaklida ekranga chiqaradigan dastur tuzing.

Kiruvchi ma'lumot

Birinchi qatorda a/b ko‘rinishidagi kasr son. Bunda a soni \(-10^8\) dan \(10^8\) gacha, b soni \(2\) dan \(10^8\) gacha.

Chiquvchi ma'lumot

a b/c ko‘rinishidagi aralash son

#include <stdio.h>
#include <itboom.h>

int main() {
    int a, b;
    scanf("%d/%d", &a, &b);
    
    int n = a / b;
    printf("%d %d/%d", n, a % b, b);

    return 0;
}

import math
import itboom

def main():
    a, b = map(int, input().split("/"))
    n = math.fmod(a, b)
    print(f"{int((a - n) / b)} {int(n)}/{b}")

if __name__ == '__main__':
    main()

Masala E

Masala sharti

Kiritilgan harfni kiritilgan qiymatcha takrorlab ekranga chiqaradigan dastur tuzing

Kiruvchi ma'lumot

nL ko‘rinishidagi matn. Bu yerda n 1 dan 9 gacha bo‘lgan son, L birorta belgi.

Chiquvchi ma'lumot

L belgini n marotaba takrorlab chiqarilgan natija

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